20y^2-245=0

Solution for 20y^2-245=0 equation:

20y^2-245=0

a = 20; b = 0; c = -245;
Δ = b2-4ac
Δ = 02-4·20·(-245)
Δ = 19600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{19600}=140$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-140}{2*20}=\frac{-140}{40}
=-3+1/2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+140}{2*20}=\frac{140}{40}
=3+1/2
$